2x^2+17x-9.1=0

Solution for 2x^2+17x-9.1=0 equation:

2x^2+17x-9.1=0

a = 2; b = 17; c = -9.1;
Δ = b2-4ac
Δ = 172-4·2·(-9.1)
Δ = 361.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{361.8}}{2*2}=\frac{-17-\sqrt{361.8}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{361.8}}{2*2}=\frac{-17+\sqrt{361.8}}{4}
$